Solving 10385 - Duathlon (Ternary search)
[and.git] / 11367 - Full tank? / comparación / 11367.3.cpp
blobc4214323430836c76c93f617902c31cd4da013b6
1 /*
2 Accepted
3 */
4 #include <iostream>
5 #include <vector>
6 #include <queue>
7 //#include <cassert>
9 using namespace std;
11 const int MAXN = 1000, MAXC = 100;
13 struct edge{
14 int i, g, w;
15 edge(){}
16 edge(int I, int G, int W) : i(I), g(G), w(W) {}
17 bool operator < (const edge &that) const {
18 return w > that.w;
22 int p[MAXN], d[MAXN][MAXC+1], n, visited, maxQSize;
23 vector<edge> g[MAXN];
26 int dijkstra(const int &start, const int &end, const int &c){
27 for (int i=0; i<n; ++i)
28 for (int j=0; j<=c; ++j)
29 d[i][j] = INT_MAX;
31 priority_queue<edge> q;
32 q.push(edge(start, 0, 0));
33 d[start][0] = 0;
35 while (q.size()){
37 maxQSize = max(maxQSize, (int)q.size());
39 edge u = q.top();
40 q.pop();
42 //printf("popped <%d, %d, %d>\n", u.i, u.g, u.w);
43 if (u.i == end){
44 return u.w;
46 if (d[u.i][u.g] < u.w) continue;
48 ++visited;
50 //I can buy another gallon and stay where I am
51 if (u.g < c && u.w + p[u.i] < d[u.i][u.g+1]){
52 d[u.i][u.g+1] = u.w + p[u.i];
53 q.push(edge(u.i, u.g+1, u.w + p[u.i]));
56 //Now try to reach each other node as long as I have enough gas
57 vector<edge> &v = g[u.i];
58 for (int j=0; j<v.size(); ++j){
59 int distance = v[j].w;
60 int neighbor = v[j].i;
61 if (u.g >= distance){
62 int new_gas = u.g - distance;
63 if (u.w < d[neighbor][new_gas]){
64 d[neighbor][new_gas] = u.w;
65 q.push(edge(neighbor, new_gas, u.w));
70 return INT_MAX;
74 int main(){
75 int m;
76 scanf("%d %d", &n, &m);
77 for (int i=0; i<n; ++i){
78 scanf("%d", &p[i]);
81 while (m--){
82 int u, v, d;
83 scanf("%d %d %d", &u, &v, &d);
84 g[u].push_back(edge(v, 0, d));
85 g[v].push_back(edge(u, 0, d));
88 int q;
89 scanf("%d", &q);
90 while (q--){
91 int c, s, e;
92 scanf("%d %d %d", &c, &s, &e);
93 visited = 0;
94 maxQSize = 0;
95 int t = dijkstra(s, e, c);
96 if (t < INT_MAX){
97 printf("%d\n", t);
98 }else{
99 printf("impossible\n");
101 printf(" Visited %d states with maximum queue size of %d\n", visited, maxQSize);
103 return 0;